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प्रश्न
| Concentration of SO2 (in ppm) | Number of days (Frequency) |
| 0.00 − 0.04 | 4 |
| 0.04 − 0.08 | 9 |
| 0.08 − 0.12 | 9 |
| 0.12 − 0.16 | 2 |
| 0.16 − 0.20 | 4 |
| 0.20 − 0.24 | 2 |
| Total | 30 |
The above frequency distribution table represents the concentration of sulphur dioxide in the air in parts per million of a certain city for 30 days. Using this table, find the probability of the concentration of sulphur dioxide in the interval 0.12 − 0.16 on any of these days.
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उत्तर
Number days for which the concentration of sulphur dioxide was in the interval of 0.12 − 0.16 = 2
Total number of days = 30
Hence, required probability, `P = 2/30 = 1/15`
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