Question

The 4th term from the end of the G.P. $$\frac{2}{27}, \frac{2}{9}, \frac{2}{3}, ......., 162$$ is ______.

पर्याय

• 18

• 2

• 6

• $$\frac{2}{3}$$

Answer 1

The 4th term from the end of the G.P. $$\frac{2}{27}, \frac{2}{9}, \frac{2}{3}, ......., 162$$ is 6.

Explanation:

The common ratio is $$3$$. The fourth term from the end is $$\frac{162}{3^3} = 6$$.