Question

The 17th term of an AP exceeds its 10th term by 21. The common difference of the AP is ______.

पर्याय

• 3

• 2

• –3

• –2

Answer 1

The 17th term of an AP exceeds its 10th term by 21. The common difference of the AP is 3.

Explanation:

(T₁₇ – T₁₀) = 21 

⇒ (a + 16d) – (a + 9d) = 21 

⇒ 7d = 21

⇒ d = `21/7`

⇒ d = 3