Advertisements
Advertisements
प्रश्न
Subtract the first rational number from the second in each of the following:
\[\frac{- 2}{3}, \frac{5}{6}\]
बेरीज
Advertisements
उत्तर
\[\frac{5}{6} - \frac{- 2}{3} = \frac{5}{6} - \frac{- 4}{6} = \frac{5 - ( - 4)}{6} = \frac{5 + 4}{6} = \frac{9}{6} = \frac{3}{2}\]
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
संबंधित प्रश्न
Evaluate each of the following:
\[\frac{- 6}{13} - \frac{- 7}{13}\]
Express each of the following as a rational number of the form \[\frac{p}{q}:\]
\[\frac{6}{7} + 1 + \frac{- 7}{9} + \frac{19}{21} + \frac{- 12}{7}\]
Simplify each of the following and express the result as a rational number in standard form:
\[\frac{- 9}{16} \times \frac{- 64}{- 27}\]
Simplify:
\[\left( \frac{1}{4} \times \frac{2}{7} \right) - \left( \frac{5}{14} \times \frac{- 2}{3} \right) + \left( \frac{3}{7} \times \frac{9}{2} \right)\]
Fill in the blanks:
\[\frac{1}{2} \times \left( \frac{3}{4} + \frac{- 5}{12} \right) = \frac{1}{2} \times . . . . . . + . . . . . . \times \frac{- 5}{12}\]
If `p/q` is a rational number, then p cannot be equal to zero.
If `r/s` is a rational number, then s cannot be equal to zero.
Every integer is a rational number but every rational number need not be an integer.
All decimal numbers are also rational numbers.
Express `3/4` as a rational number with denominator:
–80
