Question

Subtract:

2ab²c² + 4a²b²c – 5a²bc² from –10a²b²c + 4ab²c² + 2a²bc² 

Answer 1

We have,

2ab²c² + 4a²b²c – 5a²bc² and –10a²b²c + 4ab²c² + 2a²bc² 

The required difference is given by (–10a²b²c + 4ab²c² + 2a²bc²) – (2ab²c² + 4a²b²c – 5a²bc²)

= –10a²b²c + 4ab²c² + 2a²bc² – 2ab²c² – 4a²b²c + 5a²bc²

= (–10a²b²c – 4a²b²c) + (4ab²c² – 2ab²c²) + (2a²bc² + 5a²bc²)  ...[Grouping like terms]

= –14a²b²c + 2ab²c² + 7a²bc²