Advertisements
Advertisements
प्रश्न
Study the diagram alongside carefully and calculate the resultant moment of force about (a) point P (b) point Q (c) about point R which is exactly in the middle of P and Q.
Advertisements
उत्तर
(a) Moment of force due to F₁ about P = F1 × ⊥ distance
= 20 N × 0
= 0
Moment of force due to F2 about P = F2 × ⊥ distance
= \[20 \text{ N} \times \frac{20}{100} \text{ m}\]
= 4 Nm in CWD
∴ Resultant moment of force about P = 0 + 4 Nm = 4 Nm in CWD
(b) Moment of force due to F1 about Q = F1 × ⊥ distance
= \[20 \text{ N} \times \frac{20}{100} \text{ m}\]
= 4 Nm in CWD
Moment of force due to F2 about Q = F2 × ⊥ distance
= 20 N × 0
= 0
∴ Resultant moment of force about Q = 4 Nm + 0 = 4 Nm in CWD
(c) Moment of force due to F1 about R = F1 × ⊥ distance
= \[20 \text{ N} \times \frac{10}{100} \text{ m}\]
= 2 Nm in CWD
Moment of force due to F2 about R = F2 × ⊥ distance
= \[20 \text{ N} \times \frac{10}{100} \text{ m}\]
= 2 Nm in CWD
∴ Resultant moment of force about R = 2 Nm + 2 Nm
= 4 Nm in CWD
