Question

Given below are two statements:

Statement I: [Ni(CN)₄]²⁻ is square planar and diamagnetic complex with dsp² hybridization for Ni but [Ni(Co)₄] is tetrahedral, paramagnetic and with sp³ hybridization for Ni.

Statement II: [NiCl₄]²⁻ and [Ni(CO)₄] both have same d-electron configuration, have same geometry and are paramagnetic.

In light of the above statements, choose the correct answer from the options given below:

पर्याय

• Both statement I and statement II are true.

• Both statement I and statement II are false.

• Statement I is correct but statement II is false.

• Statement I is incorrect but statement II is true.

Answer 1

Both statement I and statement II are false.

Explanation:

[Ni(CN)₄]²⁻: Ni²⁺ has a d⁸ configuration. CN⁻ is a strong field ligand (SFL), leading to square planar geometry with dsp² hybridization. It is diamagnetic due to the pairing of electrons.

[Ni(Co)₄]: Ni²⁺ undergoes excitation, giving a d¹⁰ configuration. CO is also a strong field ligand (SFL), resulting in tetrahedral geometry with sp³ hybridization. It is diamagnetic because all electrons are paired.

[NiCl₄]²⁻: Ni²⁺ has a d⁸ configuration. Cl⁻ is a weak field ligand (WFL), resulting in tetrahedral geometry with sp³ hybridization. It is paramagnetic due to 2 unpaired electrons.