Question

Solve for x and y:
2x + 3y = 0, 3x + 4y = 5

Answer 1

The given system of equation is:
2x + 3y = 0 ……(i)
3x + 4y = 5 ……(ii)
On multiplying (i) by 4 and (ii) by 3, we get:
8x + 12y = 0 ……(iii)
9x + 12y = 15 …….(iv)
On subtracting (iii) from (iv) we get:

x = 15
On substituting the value of x = 15 in (i), we get:
30 + 3y = 0
⇒3y = -30
⇒y = -10
Hence, the solution is x = 15 and y = -10.