Question

Solve for x: `3x^2-2sqrt3x+2=0`

Answer 1

The given quadratic equation is`3x^2-2sqrt3x+2=0`

Comparing with the quadratic equation ax² + bx + c = 0, we have

`a=3,b=-2sqrt3,c=2`

Discriminant of the given quadratic equation,

`D=b^2-4ac=(2sqrt6)^2-4xx3xx2=24-24=0`

`therefore x= (-(-2sqrt3)+-sqrt3)/(2xx3)`    `[thereforex=(-b+-sqrtD)/(2a)]`

`rArrx=(2sqrt6)/6`

`rArrx=(sqrt6)/3`

Thus, the solution of the given quadratic equation is `x=(sqrt6)/3`