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प्रश्न
Solve using formula.
5m2 – 4m – 2 = 0
बेरीज
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उत्तर
5m2 – 4m – 2 = 0 compare with ax2 + bx + c = 0, we get
⇒ a = 5, b = – 4 and c = –2
∴ b2 – 4ac = (–4)2 – 4 (5)(–2)
= 16 – (–40)
= 16 + 40
= 56
We have the formula,
`m = (-b ± sqrt(b^2 - 4ac))/(2a)`
Substituting the values in the formula, we get,
⇒ m = `(-(-4) ± sqrt(56))/(2 xx 5)`
⇒ m = `(4 ± sqrt(4 xx 14))/(2 xx 5)`
⇒ m = `(4 ± 2sqrt(14))/(2 xx 5)`
⇒ m = `(2(2 ± sqrt14))/(2 xx 5)`
⇒ m = `(2 ± sqrt 14)/(5)`
The roots are
⇒ `m = (4 + 2sqrt(14))/10 "or" m = (4 - 2sqrt(14))/10`
⇒ `m = (2 + sqrt(14))/5 "or" m = (2 - sqrt(14))/5`
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