Advertisements
Advertisements
प्रश्न
Solve the numerical problem.
The amplitude of the magnetic field part of a harmonic EM wave in a vacuum is B0 = 5 × 10−7 T. What is the amplitude of the electric field part of the wave?
Advertisements
उत्तर
Given: B0 = 5 × 10–7 T, c = 3 × 108
To find: Amplitude of electric field (E0)
Formula: c = `"E"_0/"B"_0`
Calculation: From formula,
E0 = c × B0
= 3 × 108 × 5 × 10−7
= 150 V/m
The amplitude of the electric field is 150 V/m.
APPEARS IN
संबंधित प्रश्न
Choose the correct option.
The direction of the EM wave is given by
Answer briefly.
State two characteristics of an EM wave.
The electric field in a plane electromagnetic wave is given by Ez = 60 cos(5x + 1.5 × 109 t) V/m. Then expression for the corresponding magnetic fields is (here subscripts denote the direction of the field) ______.
The property which is not of an electromagnetic wave travelling in free space is that:
