Question

Solve the following systems of equations:

3x − 7y + 10 = 0
y − 2x − 3 = 0

Answer 1

The given system of equation is

3x − 7y + 10 = 0  ...(i)

y - 2x - 3 = 0        ...(ii)
∴ y = 2x + 3         ...(iii)

Substituting y = 2x + 3 in (i), we get,

3x − 7y + 10 = 0

3x - 7(2x + 3) + 10 = 0

3x - 14x - 21 + 10 = 0

-11x - 11 = 0

-11x = 11

x = `11/-11` = - 1

Putting x = 1 in y = 2x + 3 equation (iii), we get,

y = 2x + 3

y = 2(- 1) + 3

y = - 2 + 3

y = 1

Hence, the solution of the given system of equations is x = - 1, y = 1.