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प्रश्न
Solve the following system of linear equations graphically and shade the region between the two lines and x-axis:
3x + 2y – 4 = 0
2x – 3y – 7 = 0
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उत्तर
The given equations are:
3x + 2y − 4 = 0 .......(i)
2x − 3y − 7 = 0 .............(ii)
Putting x = 0 in equation (i) we get
`=> 3 xx 0 + 2y = 4`
`=> y = 2`
x = 0, y = 2
Putting y = 0 in equation (i) we get
`=> 3x + 2 xx 0 = 4`
`=> x = 4/3`
`x = 4/3, y = 0`
Use the following table to draw the graph.
| x | 0 | `4/3` |
| y | 2 | 0 |
The graph of (i) can be obtained by plotting the two points A(0, 2), B`(4/3, 0)`
2x - 3y - 7 = 0........(ii)
Putting x = 0 in equation (ii) we get
`=> 2 xx 0 - 3y = 7`
`=> y = -7/3`
`x = 0, y = -7/3`
Putting y = 0 in equation (ii) weget
`=> 2x - 3 xx 0 = 7`
`=> x = 7/2`
`x = 7/2, y = 0`
Use the following table to draw the graph.
| x | 0 | `7/2` |
| y | `-7/3` | 0 |
Draw the graph by plotting the two points `C(0, -7/3), D(7/2, 0)` from table

The two lines intersect at P(2, -1). The area enclosed by the lines represented by the given equations and the coordinates x-axis and shaded the area in the graph.
Hence, x = 2 and y = -1 and is the solution.
