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प्रश्न
Solve the following system of equations graphically:
6x - 3y + 2 = 7x + 1
5x + 1 = 4x - y + 2
Also, find the area of the triangle formed by these lines and x-axis in each graph.
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उत्तर
The given system of equations are
6x - 3y + 2 = 7x + 1 and 5x + 1 = 4x - y + 2
Now, 6x - 3y + 2
= 7x + 1 ....(1)
⇒ x = 1 - 3y
Corresponding values of x and y can be tabulated as :
| x | 1 | -2 | 4 |
| y | 0 | 1 | -1 |
Plotting points (1, 0), (-2, 1) and (4, -1) joining them, we get a line l1 which is the graph of equation (i).
Again, 5x + 1 = 4x - y + 2 ....(ii)
⇒ x = 1 - y
Corresponding values of x and y can be tabulated as :
| x | -1 | 3 | -2 |
| y | 2 | -2 | 3 |
Plotting points (-1, 2), (3, -2) and (-2, 3) joining them, we get a line l2 which is the graph of equation (ii).
The two lines l1 and l2 intersect at a point P(1, 0).
∴ x = 1, y = 0 is the solution of the given system of equations.
Since both the lines l1 and l2 are intersecting each other at X-axis, no triangle is formed by these lines with X-axis.
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