Advertisements
Advertisements
प्रश्न
Solve the following quadratic equations by factorization:
`5/(x - 2) - 3/(x + 6) = 4/x`
Advertisements
उत्तर
`5/(x - 2) - 3/(x + 6) = 4/x`
⇒ `(5(x + 6) - 3(x - 2))/((x - 2)(x + 6)) = 4/x`
⇒`(5x + 30 - 3x + 6)/(x^2 + 6x - 2x - 12) = 4/x`
⇒ `(2x + 36)/(x^2 + 4x - 12) = 4/x`
⇒ 4x2 + 16x – 48 = 2x2 + 36x
⇒ 2x2 – 20x – 48 = 0
⇒ x2 – 10x – 24 = 0
⇒ x2 – 12x + 2x − 24 = 0
⇒ x(x − 12) + 2(x − 12) = 0
⇒ (x – 12)(x + 2) = 0
If x – 12 = 0 or x + 2 = 0
Then x = 12 or x = −2
संबंधित प्रश्न
Solve the following quadratic equation by Factorisation method: x2 + 7x + 10 = 0
The sum of two numbers is 8 and 15 times the sum of their reciprocals is also 8. Find the numbers.
`x^2+8x-2=0`
If sin α and cos α are the roots of the equations ax2 + bx + c = 0, then b2 =
Solve the following equation: a2x2 - 3abx + 2b2 = 0
Solve equation using factorisation method:
`x + 1/x = 2.5`
The side (in cm) of a triangle containing the right angle are 5x and 3x – 1. If the area of the triangle is 60 cm². Find the sides of the triangle.
Find two consecutive integers such that the sum of their squares is 61
Solve the quadratic equation by factorisation method:
x2 – 15x + 54 = 0
For equation `1/x + 1/(x - 5) = 3/10`; one value of x is ______.
