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प्रश्न
Solve the following quadratic equation.
\[x^2 - \frac{3x}{10} - \frac{1}{10} = 0\]
बेरीज
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उत्तर
\[x^2 - \frac{3x}{10} - \frac{1}{10} = 0\]
\[\Rightarrow 10 x^2 - 3x - 1 = 0\]
Comparing the above equation with ax2 + bx + c = 0
a = 10, b = -3, c = -1
∴ Δ = b2 - 4ac
= (-3)2 - 4(10) (-1)
= 9 + 40
= 49
Now, x = `(-b±sqrt(b^2-4ac))/(2a)`
\[ \Rightarrow x = \frac{- \left( - 3 \right) \pm \sqrt{\left( - 3 \right)^2 - 4 \times 10 \times \left( - 1 \right)}}{2 \times 10}\]
\[ \Rightarrow x = \frac{3 \pm \sqrt{9 + 40}}{20}\]
\[ \Rightarrow x = \frac{3 \pm \sqrt{49}}{20}\]
\[ \Rightarrow x = \frac{3 \pm 7}{20}\]
\[ \Rightarrow x = \frac{3 + 7}{20}, \frac{3 - 7}{20}\]
\[ \Rightarrow x = \frac{10}{20}, \frac{- 4}{20}\]
\[ \Rightarrow x = \frac{1}{2}, \frac{- 1}{5}\]
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