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प्रश्न
Solve the following quadratic equation:
x2 + 6x + 5 = 0
बेरीज
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उत्तर
We write, 6x = x + 5x as x2 × 5 = 5x2 = x × 5x
∴ x2 + 6x + 5 = 0
⇒ x2 + x – 5x + 5 = 0
⇒ x(x + 1) + 5(x + 1) = 0
⇒ (x + 1)(x + 5) = 0
⇒ x + 1 = 0 or x + 5 = 0
⇒ x = –1 or x = –5
Hence, the roots of the given equation are –1 and –5.
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