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प्रश्न
Solve the following quadratic equation:
9x2 + 6x + 1 = 0
बेरीज
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उत्तर
Given:
9x2 + 6x + 1 = 0
⇒ 9x2 + 3x + 3x + 1 = 0
⇒ 3x(3x + 1) + 1(3x + 1) = 0
⇒ (3x + 1) (3x + 1) = 0
⇒ 3x + 1 = 0 or 3x + 1 = 0
⇒ `x = (-1)/3` or `x = (-1)/3`
Hence, `(-1)/3` is the root of the equation 9x2 + 6x + 1 = 0.
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