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प्रश्न
Solve the following quadratic equation:
`16/x - 1 = 15/(x + 1), x ≠ 0, -1`
बेरीज
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उत्तर
`16/x - 1 = 15/(x + 1), x ≠ 0, -1`
⇒ `16/x - 15/(x + 1) = 1`
⇒ `(16x + 16 - 15x)/(x(x + 1)) = 1`
⇒ `(x + 16)/(x^2 + x) = 1`
⇒ x2 + x = x + 16 ...(Cross multiplication)
⇒ x2 – 16 = 0
⇒ (x + 4) (x – 4) = 0
⇒ x + 4 = 0 or x – 4 = 0
⇒ x = –4 or x = 4
Hence, –4 and 4 are the roots of the given equation.
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