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प्रश्न
Solve the following quadratic equation:
15x2 – 28 = x
बेरीज
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उत्तर
Given:
15x2 – 28 = x
⇒ 15x2 – x – 28 = 0
⇒ 15x2 – (21x – 20x) – 28 = 0
⇒ 15x2 – 21x + 20x – 28 = 0
⇒ 3x(5x – 7) + 4(5x – 7) = 0
⇒ (3x + 4)(5x – 7) = 0
⇒ 3x + 4 = 0 or 5x – 7 = 0
⇒ `x = (-4)/3` or `x = 7/5`
Hence, the roots of the equation are `(-4)/3 and 7/5`.
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