Question

Solve the following quadratic equation:

12abx² – (9a² – 8b²)x – 6ab = 0

Answer 1

Given:

12abx² – (9a² – 8b²)x – 6ab = 0 

⇒ 12abx² – 9a²x + 8b²x – 6ab = 0 

⇒ 3ax(4bx – 3a) + 2b(4bx – 3a) = 0

⇒ (3ax + 2b) (4bx – 3a) = 0

⇒ 3ax + 2b = 0 or 4bx – 3a = 0  

⇒ `x = (-2b)/(3a)` or `x = (3a)/(4b)` 

Hence, the roots of the equation are `(-2b)/(3a)` and `(3a)/(4b)`.