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प्रश्न
Solve the following inequation and represent the solution on the number line in following case:
3x + 2 ≤ 5x – (4 – x)
बेरीज
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उत्तर
3x + 2 ≤ 5x – (4 – x)
Simplify the right-hand side
5x − (4 − x) = 5x − 4 + x = 6x − 4
Now the inequality becomes:
3x + 2 ≤ 6x − 4
Subtract 3x from both sides:
2 ≤ 3x − 4
Add 4 to both sides:
6 ≤ 3x
Divide both sides by 3:
x ≥ 2
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