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प्रश्न
Solve the following inequation and represent the solution on the number line in following case:
`(2-x)/2 + (4-2x)/3>0`
बेरीज
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उत्तर
`(2-x)/2 + (4-2x)/3>0`
LCM of 2 and 3 is 6. Multiply entire inequality by 6:
`6 xx((2-x)/2+(4-2x)/3) > 0`
⇒ 3(2 − x) + 2(4 − 2x) > 0
Expand both terms
3(2 − x) = 6 − 3x and 2(4 − 2x) = 8 − 4x
6 − 3x + 8 − 4x > 0
⇒ 14 − 7x > 0
14 > 7x
x < 2

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