Question

Solve the following inequalities

4n + 7 ≥ 3n + 10, n is an integer

Answer 1

4n + 7 ≥ 3n + 10

Subtracting 3n on both sides

4n + 7 – 3n ≥ 3n + 10 – 3n

n(4 – 3) + 7 ≥ 3n + 10 – 3n

n(4 – 3) + 7 ≥ n(3 – 3) + 10

n + 7 ≥ 10

Subtracting 7 on both sides

n + 7 – 7 ≥ 10 – 7

n ≥ 3

Since the solution is an integer and is greater than or equal to 3, the solution will be 3, 4, 5, 6, 7, …..

n = 3, 4, 5, 6, 7, ….