Advertisements
Advertisements
प्रश्न
Solve the following equations graphically :
x + 3y = 8
3x = 2 + 2y
Advertisements
उत्तर
x + 3y = 8
3x = 2 + 2y
x + 3y = 8 ________(1)
3x = 2 + 2y _______(2)
Now, x + 3y = 8
⇒ y = `(8 - x)/(3)`
Corresponding values of x and y can be tabulated as :
| x | -1 | 2 | 5 |
| y | 3 | 2 | 1 |
Plotting points (-1, 3), (2, 2), (5, 1) and joiniing them, we get a line I, which is the graph of equation (1).
Again, 3x = 2 + 2y
⇒ x = `(2x + 2y)/(3)`
Corresponding values of x and y can be tabulated as :
| x | 2 | 4 | 0 |
| y | 2 | 5 | -1 |
Plotting points (2, 2), (4, 5), (0, -1) and joining them, we get a line I2 which is the graph of equation (2).
The two lines I2 and I2 intersect at the point (2, 2). Hence, x = 2, y = 2 is the unique solution of the given equation.
APPEARS IN
संबंधित प्रश्न
Solve graphically the simultaneous equations given below. Take the scale as 2 cm = 1 unit on both the axes.
x - 2y - 4 = 0
2x + y = 3
Find graphically, the vertices of the triangle whose sides have the equations 2y - x = 8; 5y - x = 14 and y - 2x = 1 respectively. Take 1 cm = 1 unit on both the axes.
Solve the following equations graphically :
x = 4
`(3x)/(3) - y = 5`
Solve the following equations graphically :
3y = 5 - x
2x = y + 3
Solve the following equations graphically :
2x - 6y + 10 = 0
3x - 9y + 25 = 0
Solve the following equations graphically :
`2 + (3y)/x = (6)/x`
`(6x)/y - 5 = (4)/y`
Find graphically the vertices of the triangle, whose sides have the equations 2y - x = 8, 5y -x = 14 and y = 2x - 1.
Solve the following system of equations graphically:
6x - 3y + 2 = 7x + 1
5x + 1 = 4x - y + 2
Also, find the area of the triangle formed by these lines and x-axis in each graph.
Solve graphically
x + y = 7, x – y = 3
Solve graphically
y = 2x + 1, y + 3x – 6 = 0
