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प्रश्न
Solve the following equation using the formula:
`1/15x^2 + 5/3 = 2/3x`
बेरीज
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उत्तर
`1/15x^2 + 5/3 = 2/3x`
`=>` x2 + 25 = 10x
`=>` x2 – 10x + 25 = 0
Here a = 1, b = −10 and c = 25
Then `x = (-b +- sqrt(b^2 - 4ac))/(2a)`
= `(-(-10) +- sqrt((-10)^2 - 4(1)(25)))/(2(1))`
= `(10 +- sqrt(0))/2`
= 5
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