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प्रश्न
Solve the following equation using quadratic formula:
5x2 – 19x + 17 = 0
बेरीज
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उत्तर
Comparing equation 5x2 – 19x + 17 = 0 with ax2 + bx + c = 0, we get:
a = 5, b = –19 and c = 17.
By formula,
`x = (-b ± sqrt(b^2 - 4ac))/(2a)`
Substituting values we get:
⇒ `x = (-(-19) ± sqrt((-19)^2 - 4 xx 5 xx 17))/(2 xx 5)`
= `(19 ± sqrt(361 - 340))/10`
= `(19 ± sqrt(21))/10`
= `(19 + sqrt(21))/10` or `(19 - sqrt(21))/10`
Hence, `x = {(19 + sqrt(21))/10, (19 - sqrt(21))/10}`.
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