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प्रश्न
Solve the following equation for x, y ∈ R:
(1 – 3i) x + (2 + 5i) y = 7 + i
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उत्तर
(1 – 3i) x + (2 + 5i) y = 7 + i
∴ (x + 2y) + (– 3x + 5y)i = 7 + i
Equating real and imaginary parts, we get
x + 2y = 7 ...(i)
and – 3x + 5y = 1 ...(ii)
Equation (i) x 3 + equation (ii) gives
11y = 22
∴ y = 2
Putting y = 2 in (i), we get
x + 2(2) = 7
∴ x = 3
∴ x = 3 and y = 2.
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