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प्रश्न
Solve the following equation by factorisation method:
`5sqrt3x^2 + 7x-2sqrt3 = 0`
बेरीज
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उत्तर
Given:
`5sqrt3x^2 + 7x-2sqrt3 = 0`
Multiply the equation by `sqrt3`
`15x^2+7sqrt3x−6=0`
a = 15, b = `7sqrt3`, c = −6
a × c
= 15 × (−6)
= −90
product = −90
sum = `7sqrt3`
`10sqrt3 and -3sqrt3`
`15x^2 + 10sqrt3x - 3sqrt3 x -6 = 0`
`(15x^2+10sqrt3x) - (3sqrt3x + 6) = 0`
`5x(3x + 2sqrt3)-sqrt3(3x+2sqrt3) = 0`
`(3x + 2sqrt3)(5x-sqrt3) = 0`
`3x+2sqrt3 = 0`
`x = -(2sqrt3)/3`
`5x-sqrt3 = 0`
`x = sqrt3/5`
`x = -(2sqrt3)/3` or `x = sqrt3/5`
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