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Solve the following equation: 4^(x^2) : 4^x = 16 : 1 - Mathematics

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प्रश्न

Solve the following equation:

`4^(x^2) : 4^x = 16 : 1`

बेरीज
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उत्तर

Given: `4^(x^2) : 4^x = 16 : 1`

Step-wise calculation:

Step 1: Use the property of exponents `a^m/a^n = a^(m - n)` to simplify the left-hand side: 

`4^(x^2 - x) = 16`

Step 2: Express 16 as a power of 4:

16 = 42

Step 3: Equate the exponents since the bases are the same and both sides are positive:

x2 – x = 2

Step 4: Rearrange the equation:

x2 – x – 2 = 0

Step 5: Factorize the quadratic equation:

(x – 2)(x + 1) = 0

Step 6: Solve for (x):

x = 2 or x = –1

The solutions to the equation are x = 2 or x = –1.

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पाठ 6: Indices/Exponents - Exercise 6C [पृष्ठ १३३]

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नूतन Mathematics [English] Class 9 ICSE
पाठ 6 Indices/Exponents
Exercise 6C | Q 3. (iii) | पृष्ठ १३३
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