Advertisements
Advertisements
प्रश्न
Solve the following equation:
`4^(x^2) : 4^x = 16 : 1`
बेरीज
Advertisements
उत्तर
Given: `4^(x^2) : 4^x = 16 : 1`
Step-wise calculation:
Step 1: Use the property of exponents `a^m/a^n = a^(m - n)` to simplify the left-hand side:
`4^(x^2 - x) = 16`
Step 2: Express 16 as a power of 4:
16 = 42
Step 3: Equate the exponents since the bases are the same and both sides are positive:
x2 – x = 2
Step 4: Rearrange the equation:
x2 – x – 2 = 0
Step 5: Factorize the quadratic equation:
(x – 2)(x + 1) = 0
Step 6: Solve for (x):
x = 2 or x = –1
The solutions to the equation are x = 2 or x = –1.
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 6: Indices/Exponents - Exercise 6C [पृष्ठ १३३]
