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तामिळनाडू बोर्ड ऑफ सेकेंडरी एज्युकेशनएचएससी विज्ञान इयत्ता १२

Solve the following differential equation: ededyexydx=(xexy+y)dy

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प्रश्न

Solve the following differential equation:

`y"e"^(x/y) "d"x = (x"e"^(x/y) + y) "d"y`

बेरीज
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उत्तर

The given equation can be written as

`("d"x)/("d"y) = (x"e"^(x/y) + y)/(y"e"^(x/y))`  ........(1)

This is a Homogeneous differential equation

Put x = vy

⇒ `("d"x)/("d"y) = "v" + y * "dv"/("d"y)`

(1) ⇒ `"v" + y * "dv"/("d"y) = ("vve"^"v" + y)/(y"e"^"v")`

`"v" + y * "dv"/("d"y) = (y("ve"^"v" + 1))/(y"e"^"v")`

`y "d"/("d"y) = ("ve"^"v" + 1)/"e"^"v" - "v"`

`y "dv"/("d"y) = ("ve"^"v" + 1 - "ve"^"v")/"e"^"v"`

`y "dv"/("d"y) = 1/"e"^"v"`

Seperating the variables

`int "e"^"v" "dv" = int ("d"y)/y`

ev = log y + log c

ev = log |cy|

i.e., `"e"^(x/y)` = log |cy|  .......`[∵ "v" = x/y]`

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Solution of First Order and First Degree Differential Equations
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 10: Ordinary Differential Equations - Exercise 10.6 [पृष्ठ १६६]

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सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 12 TN Board
पाठ 10 Ordinary Differential Equations
Exercise 10.6 | Q 3 | पृष्ठ १६६

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