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प्रश्न
Solve the following differential equation:
`("d"^2y)/("d"x^2) + 16y = 0`
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उत्तर
Given (D2 + 16) y =0
The auxiliary equation is m2 + 16 = 0
⇒ m2 = – 16
⇒ m = ± 4i
It is of the form α ± iβ, α = 0, β = 4
The complementary function (C.F) is e0x [A cos 4x + B sin 4x]
The general solution is y = [A cos 4x + B sin 4x]
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