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प्रश्न
Solve for y:
`sqrt((2/5)^(y - 3)) = 39 1/16`
बेरीज
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उत्तर
We are solving:
`sqrt((2/5)^(y - 3)) = 39 1/16`
Step 1: Convert mixed fraction
`39 1/16 = (39 * 16 + 1)/16`
= `(624 + 1)/16`
= `625/16`
So equation is:
`sqrt((2/5)^(y - 3)) = 625/16`
Step 2: Remove square root
`(2/5)^(y - 3) = (625/16)^2`
Step 3: Simplify right-hand side
625 = 252 = 54,
16 = 24
So, `(625/16)^2 = (5^4/2^4)^2 = (5/2)^8`
Step 4: Rewrite left-hand side
`(2/y)^(y - 3) = (5/2)^(-(y - 3)) = (5/2)^(3 - y)`
So equation is:
`(5/2)^(3 - y) = (5/2)^8`
Step 5: Equating exponents
3 – y = 8
y = 3 – 8 = –5
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पाठ 6: Indices - MISCELLANEOUS EXERCISE [पृष्ठ ६९]
