Question

Solve for x:

log_x 32 = –5

Answer 1

Given: log_x 32 = –5

Step-wise calculation:

1. Convert to exponential form: 

x^–5 = 32

2. Solve for x: 

`x = 32^(-1/5)` 

`x = (2^5)^(-1/5)` 

x = 2^–1

`x = 1/2`