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Solve for x: log (5x + 6) + log (5x – 6) = 2 log 8 - Mathematics

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प्रश्न

Solve for x:

log (5x + 6) + log (5x – 6) = 2 log 8

बेरीज
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उत्तर

We are given:

log(5x + 6) + log(5x – 6) = 2 log 8

Step 1: Use log product rule

log[(5x + 6)(5x – 6)] = 2 log 8

Simplify both sides:

  • Left: (5x + 6)(5x – 6) = 25x2 – 36
  • Right: 2 log 8 = log 82 = log 64

So the equation becomes:

log(25x2 – 36) = log 64

Step 2: Equate the arguments

25x2 – 36 = 64

25x2 = 100

x2 = 4

⇒ x = ±2

Step 3: Check validity

  • For x = 2:
    5x + 6 = 16 > 0, 5x – 6 = 4 > 0 → valid
  • For x = –2:
    5x + 6 = –10 + 6 = – 4 < 0 → invalid

x = 2

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पाठ 7: Logarithms - EXERCISE 7B [पृष्ठ ७५]

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बी निर्मला शास्त्री Mathematics [English] Class 9 ICSE
पाठ 7 Logarithms
EXERCISE 7B | Q 3. (ix) | पृष्ठ ७५
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