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प्रश्न
Solve for x and y:
`2x - 3/y = 9, 3x + 7/y = 2 (y ≠ 0)`
बेरीज
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उत्तर
The given equations are:
`2x - 3/y = 9` ...(i)
`3x + 7/y = 2` ...(ii)
Putting `1/y = v`, we get:
2x – 3v = 6 ...(iii)
3x + 7v = 2 ...(iv)
On multiplying (iii) by 7 and (iv) by 3, we get:
14x – 21v = 63 ...(v)
9x + 21v = 6 ...(vi)
On adding (v) from (vi), we get:
23x = 69 ⇒ x = 3
On substituting x = 3 in (i), we get:
`2 xx 3 - 3/y = 9`
⇒ `6 - 3/y = 9`
⇒ `3/y = -3`
⇒ y = –1
Hence, the required solution is x = 3 and y = –1.
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