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Solve for x:
`(a/b)^(1 - 2x) = root(3)(b/a)`
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Given expression is `(a/b)^(1 - 2x) = root(3)(b/a)`.
We have to find the value of x in the given expression.
Thus, `(a/b)^(1 - 2x) = root(3)(b/a)`
`(a/b)^(1 - 2x) = (b/a)^(1/3)` ...`[∴ root(n)(a) = a^(1/n)]`
`(a/b)^(1 - 2x) = (a/b)^((-1)/3)` ...`[∴ (a/b)^n = (b/a)^-n]`
Equating the powers with same bases.
`1 - 2x = (-1)/3`
3(1 – 2x) = –1
3 – 6x = –1
4 = 6x
`x = 4/6`
`x = 2/3`
Therefore, the value of x in the given expression is `2/3`.
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