Advertisements
Advertisements
प्रश्न
Solve the following quadratic equation using formula method only
`sqrt 3 "x"^2 + 10 "x" - 8 sqrt 3 = 0`
Advertisements
उत्तर
`sqrt 3 "x"^2 + 10 "x" - 8 sqrt 3 = 0`
a = `sqrt 3` ; b = 10 ; c = `-8/sqrt 3`
D = b2 - 4ac
= `(10)^2 - 4 (sqrt 3) (-8 sqrt 3)`
= 100 + 96
= 196
x = `(- "b" ± sqrt ("b"^2 - 4 "ac"))/(2a)`
x = `(- 10 +- sqrt 196)/(2 sqrt 3)`
x = `(-10 + 14)/(2 sqrt 3)` , x = `(-10 - 14)/(2 sqrt 3)`
x = `4/(2 sqrt 3)` , x = `24/(2 sqrt 3)`
x = `2/sqrt 3` , x = `-12/ sqrt 3`
APPEARS IN
संबंधित प्रश्न
Find the values of k for which the given quadratic equation has real and distinct roots:
kx2 + 6x + 1 = 0
Determine, if 3 is a root of the given equation
`sqrt(x^2 - 4x + 3) + sqrt(x^2 - 9) = sqrt(4x^2 - 14x + 16)`.
If x = 2 and x = 3 are roots of the equation 3x² – 2kx + 2m = 0. Find the values of k and m.
Find the value of k for which the given equation has real roots:
kx2 - 6x - 2 = 0
Determine whether the given quadratic equations have equal roots and if so, find the roots:
x2 + 2x + 4 = 0
Choose the correct answer from the given four options :
If the equation 3x² – kx + 2k =0 roots, then the the value(s) of k is (are)
α and β are the roots of 4x2 + 3x + 7 = 0, then the value of `1/α + 1/β` is:
The roots of the equation (b – c) x2 + (c – a) x + (a – b) = 0 are equal, then:
Solve the equation: 3x2 – 8x – 1 = 0 for x.
Statement A (Assertion): If 5 + `sqrt(7)` is a root of a quadratic equation with rational co-efficients, then its other root is 5 – `sqrt(7)`.
Statement R (Reason): Surd roots of a quadratic equation with rational co-efficients occur in conjugate pairs.
