Advertisements
Advertisements
प्रश्न
Solve the following equation: `10"x" - 1/"x" = 3`
Advertisements
उत्तर
`10"x" - 1/"x" = 3`
10x2 - 1 = 3x
10x2 - 3x - 1 = 0
`"x"^2 - 3/10 "x" - 1/10 = 0`
`"x"^2 + 1/5 "x" - 1/2 "x" - 1/10 = 0`
`"x" ("x" + 1/5) - 1/2 ("x" + 1/5) = 0`
`("x" + 1/5)("x" - 1/2) = 0`
`("x" + 1/5) = 0` , `("x" - 1/2) = 0`
x = `-1/5` , `x = 1/2`
APPEARS IN
संबंधित प्रश्न
Solve the following quadratic equations by factorization:
4x2 + 4bx - (a2 - b2) = 0
Solve the following quadratic equations by factorization:
abx2 + (b2 – ac)x – bc = 0
Solve the following quadratic equations by factorization:
`4(2x – 3)^2 – (2x – 3) – 14 = 0`
Solve the following equation: `("a+b")^2 "x"^2 - 4 "abx" - ("a - b")^2 = 0`
Solve the following equation by factorization
3x2 – 5x – 12 = 0
Solve the following equation by factorization.
a2x2 + 2ax + 1 = 0, a ≠ 0
The polynomial equation x(x + 1) + 8 = (x + 2) (x – 2) is:
A natural number, when increased by 12, equals 160 times its reciprocal. Find the number.
If x = –2 is the common solution of quadratic equations ax2 + x – 3a = 0 and x2 + bx + b = 0, then find the value of a2b.
Find the roots of the quadratic equation x2 – x – 2 = 0.
