Advertisements
Advertisements
प्रश्न
Solve the following equation: `1/("x" - 1) + 2/("x" - 1) = 6/"x" , (x ≠ 0)`
Advertisements
उत्तर
`1/("x" - 1) + 2/("x" - 1) = 6/"x" , (x ≠ 0)`
`(("x" - 1) + 2 ("x" - 2))/(("x" - 2)("x" - 1)) = 6/"x"`
x(x + 1) + 2x(x - 2) = 6(x - 2)(x - 1)
x2 - x + 2x2 - 4x = 6(x2 - 2x - x + 2)
3x2 - 5x = 6x2 - 18x + 12
3x2 - 13x + 12 = 0
`"x"^2 - 13/3 "x" + 4 = 0`
`"x"^2 - 3"x" - 4/3 "x" + 4 = 0`
`"x"("x" - 3) - 4/3 ("x" - 3) = 0`
`("x" - 3)("x" - 4/3) = 0`
x = 3 , x = `4/3`
APPEARS IN
संबंधित प्रश्न
Solve for x
`(2x)/(x-3)+1/(2x+3)+(3x+9)/((x-3)(2x+3)) = 0, x!=3,`
Find the roots of the following quadratic equation by factorisation:
2x2 + x – 6 = 0
Find two consecutive positive integers, sum of whose squares is 365.
Find the consecutive even integers whose squares have the sum 340.
Solve:
x(x + 1) + (x + 2)(x + 3) = 42
Solve the following quadratic equations by factorization:
`100/x-100/(x+5)=1`
Solve the following quadratic equations by factorization:
`(1 + 1/(x + 1))(1 - 1/(x - 1)) = 7/8`
The product of a girl's age five years ago and her age 3 years later is 105. Find her present age.
Solve the following equation by factorization
`x/(x - 1) + (x - 1)/x = 2(1)/(2)`
If `x + 1/x = 2.5`, the value of x is ______.
