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प्रश्न
Solve: `(3"x" - 2)/3 + (2"x" + 3)/2 = "x" + 7/6`
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उत्तर
`(3"x" - 2)/3 + (2"x" + 3)/2 = "x" + 7/6`
`=> (2(3"x" - 2) + 3("2x" + 3))/6 = "x" + 7/6`
`=> ("6x" - 4 + "6x" + 9)/6 = ("6x" + 7)/6`
`=> ("12x" + 5)/6 = ("6x" + 7)/6`
⇒ 6(12x + 5) = 6(6x + 7)
⇒ 72x + 30 = 36x - 42
⇒ 72x - 36x = 42 - 30
⇒ 36x = 12
x = `12/36`
∴ x = `1/3`
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