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प्रश्न
Since \[p\cos\theta = \vec{p} \cdot \hat{r}\], the dipole potential at a point (r >> a) written in compact vector form is:
पर्याय
\[V = \frac{1}{4\pi\varepsilon_0}\frac{|\vec{p}|}{r^2}\]
\[V = \frac{1}{4\pi\varepsilon_0}\frac{\vec{p} \times \hat{r}}{r^2}\]
\[V = \frac{1}{4\pi\varepsilon_0}\frac{\vec{p} \cdot \hat{r}}{r}\]
\[V = \frac{1}{4\pi\varepsilon_0}\frac{\vec{p} \cdot \hat{r}}{r^2}\]
MCQ
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उत्तर
p cos θ is the component of the dipole moment along the unit vector r̂, which is exactly the dot product p⃗ · r̂. The cross product would produce a vector, which cannot represent the scalar potential.
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