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प्रश्न
Simplify:
`(sqrt(6) + sqrt(10))/(sqrt(27) + sqrt(45))`
सोपे रूप द्या
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उत्तर
`(sqrt(6) + sqrt(10))/(sqrt(27) + sqrt(45))`
Step 1: Simplify each square root
- `sqrt(27) = sqrt(9 xx 3) = 3sqrt(3)`
- `sqrt(45) = sqrt(9 xx 5) = 3sqrt(5)`
So the denominator becomes `3sqrt(3) + 3sqrt(5) = 3(sqrt(3) + sqrt(5))`.
Step 2: Rewrite numerator
`sqrt(6) + sqrt(10)` cannot be simplified further into integers, so we leave it as is.
So the expression becomes `(sqrt(6) + sqrt(10))/(3(sqrt(3) + sqrt(5))`.
Step 3: Factor numerator cleverly
Notice: `sqrt(6) + sqrt(10)`
= `sqrt(2 xx 3) + sqrt(2 xx 5)`
= `sqrt(2)(sqrt(3) + sqrt(5))`
So numerator = `sqrt(2)(sqrt(3) + sqrt(5))`.
Step 4: Cancel common factor
`(sqrt(2)(sqrt(3) + sqrt(5)))/(3(sqrt(3) + sqrt(5))`
Cancel `(sqrt(3) + sqrt(5)) = sqrt(2)/3`.
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पाठ 1: Rational and Irrational Numbers - MISCELLANEOUS EXERCISE [पृष्ठ १८]
