मराठी

Simplify and express with a positive index. 5√32⁢𝑎^5⁢𝑏^10⁢𝑐^−15 - Mathematics

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प्रश्न

Simplify and express with a positive index.

`root(5)(32a^5b^10c^-15)`

सोपे रूप द्या
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उत्तर

Given,

`root(5)(32a^5b^10c^-15)`

We need to simplify and express with a positive index the given terms.

We know that if a, b, c are any non-zero integers and m and n are the whole numbers, then we have,

`root(5)(32a^5b^10c^-15)`

⇒ `(32a^5b^10c^-15)^(1/5)`   ...`[∴ root(n)(a) = a^(1/n)]`

⇒ `32^(1/5) xx (a^5)^(1/5) xx (b^10)^(1/5) xx (c^-15)^(1/5)`  ...[∴ (ab)n = an × bn]

⇒ `(2^5)^(1/5) xx (a^5)^(1/5) xx (b^10)^(1/5) xx (c^-15)^(1/5)`

⇒ `(2)^(5 xx 1/5) xx (a)^(5 xx 1/5) xx (b)^(10 xx 1/5) xx (c)^(-15 xx 1/5)`  ...[∴ (an)m = anm]

⇒ `(2) xx (a) xx (b)^2 xx (c)^-3`

⇒ `2ab^2 xx 1/c^3`  ...`[∴ a^-n = 1/a^n]`

⇒ `(2ab^2)/c^3`

Hence, `root(5)(32a^5b^10c^-15) = (2ab^2)/c^3`.

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पाठ 6: Indices - EXERCISE 6 [पृष्ठ ६६]

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बी निर्मला शास्त्री Mathematics [English] Class 9 ICSE
पाठ 6 Indices
EXERCISE 6 | Q 5. (ii) | पृष्ठ ६६
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