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प्रश्न
Simplify:
`(8/125)^(1/3)[(4/9)^(-1/2) ÷ (2/5)^2]`
सोपे रूप द्या
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उत्तर
Given,
`(8/125)^(1/3)[(4/9)^(-1/2) ÷ (2/5)^2]`
We need to simplify the given terms.
Thus, `(8/125)^(1/3)[(4/9)^(-1/2) ÷ (2/5)^2]`
⇒ `(2^3/5^3)^(1/3) [(2^2/3^2)^(-1/2) ÷ (2/5)^2]`
⇒ `(2/5)^(3 xx 1/3) [(2/3)^(2 xx (-1)/2) ÷ (2/5)^2]` ...[∴ (an)m = anm]
⇒ `(2/5) [(2/3)^-1 ÷ (2/5)^2]`
⇒ `(2/5) [3/2 xx 5/2 xx 5/2]` ...`[∵ (a/b)^-n = (b/a)^n, a/b ÷ c/d = a/b xx d/c]`
⇒ `2/5 xx 3/2 xx 5/2 xx 5/2`
= `15/4`
= `3 3/4`
Hence, the required is `3 3/4`.
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पाठ 6: Indices - EXERCISE 6 [पृष्ठ ६७]
