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प्रश्न
Simplify:
`((512a^6)/(729b^-9))^((-2)/3)`
सोपे रूप द्या
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उत्तर
We are asked to simplify:
`((512a^6)/(729b^-9))^(-2/3)`
Step 1: Recognize bases
- 512 = 83 = 29
- 729 = 93 = 36
So the expression becomes:
`((2^9a^6)/(3^6b^-9))^(-2/3)`
Step 2: Simplify inside
Since b–9 is in denominator, it goes up:
`((2^9a^6b^9)/(3^6))^(-2/3)`
Step 3: Apply the exponent `-2/3`
Raise each factor:
= `(2^9)^(-2/3) * (a^6)^(-2/3) * (b^9)^(-2/3) * (3^6)^(2/3)`
Step 4: Simplify exponents
`(2^9)^(-2/3) = 2^(9* - 2/3) = 2^-6 = 1/2^6 = 1/64`
`(a^6)^(-2/3) = a^(6* - 2/3) = a^-4 = 1/a^4`
`(b^9)^(-2/3) = b^(9* -2/3) = b^-6 = 1/b^6`
`(3^6)^(2/3) = 3^(6 * 2/3) = 3^4 = 81`
Step 5: Combine
= `81/(64a^4b^6)`
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पाठ 6: Indices - MISCELLANEOUS EXERCISE [पृष्ठ ६९]
