Advertisements
Advertisements
प्रश्न
Simplify:
(3x + 2y)(4x + 3y) − (2x − y)(7x − 3y)
Advertisements
उत्तर
To simplify, we will proceed as follows:
\[\left( 3x + 2y \right)\left( 4x + 3y \right) - \left( 2x - y \right)\left( 7x - 3y \right)\]
\[ = \left[ \left( 3x + 2y \right)\left( 4x + 3y \right) \right] - \left[ \left( 2x - y \right)\left( 7x - 3y \right) \right]\]
\[= \left[ 3x\left( 4x + 3y \right) + 2y\left( 4x + 3y \right) \right] - \left[ 2x\left( 7x - 3y \right) - y\left( 7x - 3y \right) \right]\] (Distributive law)
\[= 12 x^2 + 9xy + 8xy + 6 y^2 - \left[ 14 x^2 - 6xy - 7xy + 3 y^2 \right]\]
\[ = 12 x^2 + 9xy + 8xy + 6 y^2 - 14 x^2 + 6xy + 7xy - 3 y^2\]
\[= 12 x^2 - 14 x^2 + 9xy + 8xy + 6xy + 7xy + 6 y^2 - 3 y^2\] (Rearranging)
\[= - 2 x^2 + 30xy + 3 y^2\] (Combining like terms)
Thus, the answer is \[- 2 x^2 + 30xy + 3 y^2\].
APPEARS IN
संबंधित प्रश्न
Find each of the following product:
(2.3xy) × (0.1x) × (0.16)
Write down the product of −8x2y6 and −20xy. Verify the product for x = 2.5, y = 1.
Evaluate each of the following when x = 2, y = −1.
\[\left( \frac{3}{5} x^2 y \right) \times \left( - \frac{15}{4}x y^2 \right) \times \left( \frac{7}{9} x^2 y^2 \right)\]
Find the following product: \[- \frac{4}{27}xyz\left( \frac{9}{2} x^2 yz - \frac{3}{4}xy z^2 \right)\]
Find the product 24x2 (1 − 2x) and evaluate its value for x = 3.
Multiply:
(a − 1) by (0.1a2 + 3)
Multiply:
(2x2y2 − 5xy2) by (x2 − y2)
Multiply:
(3x2y − 5xy2) by \[\left( \frac{1}{5} x^2 + \frac{1}{3} y^2 \right)\].
Simplify:
(x3 − 2x2 + 5x − 7)(2x − 3)
Show that: (9a − 5b)2 + 180ab = (9a + 5b)2
