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Simplify: (ЁЭСО + 1/ЁЭСП)^ЁЭСе тБв(ЁЭСО тИТ 1/ЁЭСП)^ЁЭСж/(ЁЭСП + 1/ЁЭСО)^ЁЭСе тБв(ЁЭСП тИТ 1/ЁЭСО)^ЁЭСж - Mathematics

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Simplify:

`((a + 1/b)^x (a - 1/b)^y)/((b + 1/a)^x (b - 1/a)^y)`

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We are asked to simplify:

`((a + 1/b)^x * (a - 1/b)^y)/((b + 1/a)^x * (b - 1/a)^y)`

Step 1: Rewrite denominator terms

`b + 1/a = (ab + 1)/a`,

`b - 1/a = (ab - 1)/a`

So denominator becomes:

`((ab + 1)/a)^x * ((ab - 1)/a)^y`

Step 2: Rewrite numerator terms

`a + 1/b = (ab + 1)/b`,

`a - 1/b = (ab - 1)/b`

So numerator becomes:

`((ab + 1)/b)^x * ((ab - 1)/b)^y`

Step 3: Form fraction

`(((ab + 1)/b)^x * ((ab - 1)/b)^y)/(((ab + 1)/a)^x * ((ab - 1)/a)^y)`

Step 4: Simplify

Separate terms:

= `((ab + 1)/b)^x/((ab + 1)/a)^x * ((ab - 1)/b)^y/((ab - 1)/a)^y`

Simplify each fraction:

  • First fraction:
    `((ab + 1)/b)^x/((ab + 1)/a)^x = (a/b)^x`
  • Second fraction:
    `((ab - 1)/b)^y/((ab - 1)/a)^y = (a/b)^y`

Step 5: Combine

`(a/b)^x * (a/b)^y = (a/b)^(x + y)`

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рдкрд╛рда 6: Indices - MISCELLANEOUS EXERCISE [рдкреГрд╖реНрда ремреп]

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рдмреА рдирд┐рд░реНрдорд▓рд╛ рд╢рд╛рд╕реНрддреНрд░реА Mathematics [English] Class 9 ICSE
рдкрд╛рда 6 Indices
MISCELLANEOUS EXERCISE | Q 1. (vi) | рдкреГрд╖реНрда ремреп
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