Advertisements
Advertisements
प्रश्न
Simplify:
`(sqrt0.2304+sqrt0.1764)/(sqrt0.2304-sqrt0.1764)`
Advertisements
उत्तर
We have:
`sqrt0.2304=sqrt(2304/10000)`
=`sqrt(2xx2xx2xx2xx2xx2xx2xx2xx3xx3)/100`
=`(2xx2xx2xx2xx3)/100`
=0.48
`sqrt0.1764=sqrt(1764/10000)`
=`sqrt(2xx2xx3xx3xx7xx7)/100`
=`(2xx3xx7)/100`
=`0.42`
`(sqrt0.2304+sqrt0.1764)/(sqrt0.2304-sqrt0.1764)=(0.48+0.42)/(0.48-0.42)=0.9/0.06=15`
APPEARS IN
संबंधित प्रश्न
Find the square root in decimal form:
225.6004
Find the square root the following correct to three places of decimal.
237.615
Find the square root the following correct to three places of decimal.
15.3215
Find the square root the following correct to three places of decimal.
0.019
Find the square root the following correct to three places of decimal.
`5/12`
Find the square root the following correct to three places of decimal.
`287 5/8`
Given that: \[\sqrt{2} = 1 . 414, \sqrt{3} = 1 . 732, \sqrt{5} = 2 . 236 \text{ and } \sqrt{7} = 2 . 646,\]evaluate the following:
\[\sqrt{\frac{2500}{3}}\]
Given that:
\[\sqrt{2} = 1 . 414, \sqrt{3} = 1 . 732, \sqrt{5} = 2 . 236 \text{ and } \sqrt{7} = 2 . 646,\]ind the square roots of the following:
\[\frac{196}{75}\]
Given that:
\[\sqrt{2} = 1 . 414, \sqrt{3} = 1 . 732, \sqrt{5} = 2 . 236 \text{ and } \sqrt{7} = 2 . 646,\] find the square roots of the following:
\[\frac{400}{63}\]
A decimal number is multiplied by itself. If the product is 51.84, find the number.
