Advertisements
Advertisements
प्रश्न
Show that the following points taken in order to form an isosceles triangle
A(6, −4), B(−2, −4), C(2, 10)
Advertisements
उत्तर
Distance = `sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2`
AB = `sqrt((-2 - 6)^2 + (-4 + 4)^2`
= `sqrt((-8)^2 + 0)`
= `sqrt(64)`
= 8
BC = `sqrt((2 + 2)^2 + (10 + 4)^2`
= `sqrt((4)^2 + (14)^2`
= `sqrt(16 + 196)`
= `sqrt(212)`
AC = `sqrt((2 - 6)^2 + (10 + 4)^2`
= `sqrt((- 4)^2 + (14)^2`
= `sqrt(16 + 196)`
= `sqrt(212)`
BC = AC = `sqrt(212)` ...(Two sides are equal)
∴ ABC is an isosceles triangle.
APPEARS IN
संबंधित प्रश्न
If the co-ordinate of A is x and that of B is y, find d(A, B).
x = 1, y = 7
Sketch proper figure and write the answer of the following question.
If R-S-T and l(ST) = 3.7, l(RS) = 2.5, then l(RT) = ?
Sketch proper figure and write the answer of the following question.
If X-Y-Z and l(XZ) = `3sqrt7`, l(XY) = `sqrt7`, then l(YZ) = ?
On a number line, co-ordinates of P, Q, R are 3, -5 and 6 respectively. State with reason whether the following statement is true or false.
d(P, Q) - d(P, R) = d(Q, R)
Co-ordinates of the pair of points are given below. Hence find the distance between the pair.
- 4, 5
Co-ordinates of the pair of points are given below. Hence find the distance between the pair.
0, - 2
Co-ordinates of the pair of points are given below. Hence find the distance between the pair.
- 25, - 47
Co-ordinate of point A on a number line is 1. What are the co-ordinates of points on the number line which are at a distance of 7 units from A?
The point whose ordinate is 4 and which lies on the y-axis is _______________
Find the distance with the help of the number line given below.
d(K, O)
